Range.fuzzyAssign

Apply a prob chance that this equals val.

  1. Range!T fuzzyAssign(Range!T val, double prob)
  2. Range!T fuzzyAssign(T val, double prob)
    struct Range(T)
    fuzzyAssign
    (
    T val
    ,
    double prob = 0.5
    )
  3. T lo;
  4. T hi;
  5. T avg;

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